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vovikov84 [41]
2 years ago
15

Question 1 of 13

Mathematics
1 answer:
Scilla [17]2 years ago
6 0

Answer:

I'm here to help. If you can put a picture of the answer choices I can give you the answer!

Step-by-step explanation:

You might be interested in
Bamboo Plant A is 1.2 meters tall and growing at a rate of 0.45 meter per day. Bamboo Plant B is 0.85 meter tall and growing 0.5
pashok25 [27]

Answer:

7 days

Step-by-step explanation:

Bamboo plant A = 1.2 + 0.45d

Bamboo plant B = 0.85 + 0.5d

Where,

d = number of days

Equate the two growth

Bamboo plant A = Bamboo plant B

1.2 + 0.45d = 0.85 + 0.5d

Collect like terms

1.2 - 0.85 = 0.5d - 0.45d

0.35 = 0.05d

Divide both sides by 0.05

d = 0.35 / 0.05

d = 7 days

Plant B be taller than Plant A after 7 days

3 0
3 years ago
Mark wants to find the area of a circle with a diameter of 6 cm. Which expressions can he use to find the area of the circle in
ANEK [815]

Answer:

B and C

(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e

8 0
3 years ago
Read 2 more answers
If the answer is correct you get brainly
yarga [219]

Answer:

the answer is 2,800.

Step-by-step explanation:

5x5x2x7x8=2,800.

7 0
3 years ago
What is the substitution to 3x y=-16 5x y=-20?
erica [24]
The first one ,to substitute 3xy from -16 ...so divided both side by 3 .so, (xy =-5.33). the second one,5xy =-20. so,divided both sides by 5 so xy = -4....
5 0
3 years ago
If the angle between each blade of the wind turbine is the same, and each blade has a length of 20 meters, find the distance bet
Ket [755]

A typical windmill has three blades. We can envision these blades in a circle, which a circle = 360 degrees. We want to divide up the angles of the blades so they are even or makes up 360 degrees. We have three blades so we have 3 angles to divide by 360 degrees. So, 360 / 3 = 120 degrees. Now that we know the angle of the blades, we can use the Law of Cos to solve the distance between the blade tip.


Law of Cos

c^2 = a^2 + b^2 - 2(a)(b)(\cos A)


We know

a = 20

b = 20

A = Angle = 120


We need to solve for c

c^2 = a^2 + b^2 - 2(a)(b)(\cos A)


Take the square root of each side of the =

\sqrt{c^2} = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

c = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

Input the values we know into the formula and solve for c:

c = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

c = \sqrt{20^2 + 20^2 - 2(20)(20)(\cos 120)}

c = \sqrt{400 + 400 - 2(20)(20)(\cos 120)}

c = \sqrt{800 - 2(20)(20)(\cos 120)}

c = \sqrt{800 - 2(400)(\cos 120)}

c = \sqrt{800 - 800(\cos 120)}

c = \sqrt{800 - (-400)}

c = \sqrt{1200}

c = 20\sqrt{3}

c = 34.641016

c = 34.64


We now have our answer, which is 34.64 and that is C.






3 0
4 years ago
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