You will need option A
AB = PQ
If I'm not wrong I believe it would be 343 different ways.
Answer:
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
Step-by-step explanation:
Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6
Y can only take values of 2, 3 and 4
So, Probability of Y = P(Y) = 1C(Y-1) / 6
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
Let s = northbound train
Then
2s = southbound train
:
Distance = time * speed
4s + 4(2s) = 600
:
4s + 8s = 600
:
12s = 600
:
s = 600/12
:
s = 50 mph is the northbound train
Then
2(50) = 100 mph is the southbound train
:
:
Check:
4(50) + 4(100) = 600
-- To play the six games, <span>Santiago Diaz Granados spent
(6 x 25) = 150 tokens.
-- As a result of his skill, experience, talent, steady hand, nerves
of steel, superior hand-eye coordination, and superb reflexes, </span><span>
Santiago Diaz Granados won</span>
(0 + 10 + 50 + 0 + 5 + 10) = 75 tokens.
-- At the end of the 6th game, <span>Santiago Diaz Granados was behind
the curve.
After spending 150 tokens and winning 75 tokens, </span><span>Santiago Diaz Granados
was down by (150 - 75) = 75 tokens since he arrived at the arcade.
Any true friend could look at the choices, could see that choice-B is
the correct one, and could advise </span><span>Santiago Diaz Granados to cash in
whatever he had left, accept his losses, return to his home, and live
to fight another day.
Viva </span><span>Santiago Diaz Granados ... </span><span>un verdadero héroe de su pueblo. Viva !</span>
