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Using synthetic division, we find the result of the division
(6x^4 +2x^3 -6x^2 -14x -1)/(3(x +1/3))
to be ...
(6x^3 -6x -12)/3 +3/(3x +1)
The result is ...
2x^3 -2x -4 +3/(3x+1)
(6x^4 +2x^3 -6x^2 -14x -1)/(3(x +1/3))
to be ...
(6x^3 -6x -12)/3 +3/(3x +1)
The result is ...
2x^3 -2x -4 +3/(3x+1)
now, notice, we use the decimal format for the percent, namely 17% is 17/100 or 0.17 and so on
so.... we know, whatever "x" and "y" is, they must add up to 100 grams
thus x + y = 100
and whatever the concentrated amount is, it must add up to 17 grams for the composition
thus 0.1x + 0.2y = 17
solve for "x", to see how much is needed of the 10% alloy
what about "y"? well, y = 100 - x