Y+bx=n(56+56-75686=86) 56+74=6446-647=89
Solve the equation:
3e^(2x + 1) = 12
e^(2x + 1) = 12/3
e^(2x + 1) = 4
2x + 1 = ln(4)
2x + 1 = ln(2^2)
2x + 1 = 2 ln(2)
2x = 2 ln(2) - 1
x = [ 2 ln(2) - 1 ] / 2 <----- this is the answer.
________
Checking:
2x + 1 = 2 ln(2)
2x + 1 = ln(4)
e^(2x + 1) = e^[ ln(4) ]
e^(2x + 1) = 4
3e^(2x + 1) = 3 * 4
3e^(2x + 1) = 12 (checked)
I hope this helps. :-)
Part A:
Company A equation: 22d+5=c
Company B equation: 20d+16=c
"d" represents the number of days
"c" represents the total cost
Part B:
If you rented a car from Company B for 9 days it would be less than if you rented a car from Company A for 9 days. If you plug 9 in for "d" in both equations, Company A's total cost would be $203, while Company B's would be $196.
Part C:
You would save $19.
Hope this helps!
The answer is for
5) 15i√3
8)-39√14