We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

3 years ago

How does a digit in the 10,000s place compare to a digit in the thousands place?

Delvig [45]

While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that a digit in the ten thousand place values ten times what the same digit values is it is the thousand place.

4 0

3 years ago

I need help!!! Please help me cuties<br> REPORTING LINKS!!

vitfil [10]

Answer:

1. 15.4

2. 9.66

3. 13.16

4. 12.32

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do you answer this ?

telo118 [61]

6 x 10 =60
40 x 24=960
maybe
I REALLY DON'T KNOW

8 0

3 years ago