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2 years ago

Please answer all 5 xoxo <3

Mathematics

1 answer:

romanna [79]2 years ago

5 0

Answer:

First Image: Option D

Second Image: Option D

Third Image: Option C

Fourth Image: Option B

Fifth Image: Option B

Step-by-step explanation:

First Image:

Supplementary angles is two angles whose sum is 180 degrees (straight line)
180 - 47 = 133°
? is an obtuse angle is any angle greater than 90° which checks the answer

Second Image:

A triangle angles adds up to 180°
Two angles are already given
72 + 45 + ? = 180° → 117 + ? = 180° → ? = 63°
? is an acute angle is an angle that measures between 90° and 0°

Third Image:

Supplementary angles is two angles whose sum is 180 degrees (straight line)
180 - 110 = 70°
? is an acute angle is an angle that measures between 90° and 0°

Fourth Image:

Supplementary angles is two angles whose sum is 180 degrees (straight line)
180 - 120 = 60°
we are shown a right angle which = 90°
A triangle adds up to 180°
180 - 90 - 60 = 30
? = 30°
? is an acute angle is an angle that measures between 90° and 0°

Fifth Image:

Supplementary angles is two angles whose sum is 180 degrees (straight line)
180 - 85 = 95°
? is an obtuse angle is any angle greater than 90° which checks the answer

Learn more about Triangles here: brainly.com/question/4186813

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What 2 digit numbers multiply to 2,025

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Square root 2,025 to get 45.
Or, multiply 45 × 45 to get 2,025.

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Sid earns $135 per day as a babysitter. He works 9 hours each day. How much does he earn in an hour?

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Sid earns $15 an hour.
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The number which when added to its half gives 30. What is the number?

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Answer:

Step-by-step explanation:

half of 20 is 10.

so 20 + 10 = 30

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3 years ago

HALLP QUICKKKK

Rina8888 [55]

To solve this we are going to use the formula for speed: $S= \frac{d}{t}$
where
$S$ is the speed
$d$ is the distance
$t$ is the time

Let $S_{l}$ be the speed of the boat in the lake, $S_{a}$ the speed of the boat in the river, $t_{l}$ the time of the boat in the lake, and $t_{a}$ the time of the boat in the river.

We know for our problem that the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
 $S_{a}=S_{l}-2$
We also know that in the lake the boat sailed for 1 hour longer than it sailed in the river, so:
 $t_{l}=t_{a}+1$

Now, we can set up our equations.
Speed of the boat traveling in the river:
 $S_{a}= \frac{6}{t_{a} }$
But we know that $S_{a}=S_{l}-2$ , so:
$S_{l}-2= \frac{6}{t_{a} }$ equation (1)

Speed of the boat traveling in the lake:
$S_{l}= \frac{15}{t_{l} }$
But we know that $t_{l}=t_{a}+1$ , so:
$S_{l}= \frac{15}{t_{a}+1}$ equation (2)

Solving for $t_{a}$ in equation (1):
$S_{l}-2= \frac{6}{t_{a} }$
$t_{a}= \frac{6}{S_{l}-2}$ equation (3)

Solving for $t_{a}$ in equation (2):
$S_{l}= \frac{15}{t_{a}+1}$
$t_{a}+1= \frac{15}{S_{l}}$
$t_{a}=\frac{15}{S_{l}}-1$
$t_{a}= \frac{15-S_{l}}{S_{l}}$ equation (4)

Replacing equation (4) in equation (3):
$t_{a}= \frac{6}{S_{l}-2}$
$\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}$

Solving for $S_{l}$ :
$\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}$
$(15-S_{l})(S_{l}-2)=6S_{l}$
$15S_{l}-30-S_{l}^2+2S_{l}=6S_{l}$
$S_{l}^2-11S_{l}+30=0$
$(S_{l}-6)(S_{l}-5)=0$
$S_{l}=6$ or $S_{l}=5$

We can conclude that the speed of the boat traveling in the lake was either 6 km/hour or 5 km/hour.

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natta225 [31]

3/4 root 10
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