Let x be the unknown number. This means that "six times a number" becomes 6x. Finally, we want to compute the quotient between this quantity and 16, which leads to

Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
Answer:
$49425.1688842
Step-by-step explanation:
Use formula: v=c*(p^t), where v is the price now, c is the cost price, p is the 100-the depreciation percentage and t is the time/years passed)
0.9¹²(175000)
0.28242953648(175000)
49425.1688842
There are only two significant digits in the measurement. Everything after the decimal point is 00 - so those two zeros are not significant. The answer is A - two numbers are significant.