All categories

3 years ago

What's the Answer To 9 Hundreds Place And The 6 In The Hundreds

Mathematics

2 answers:

Andrews [41]3 years ago

8 0

Between the two answer is 3 hundred

lisabon 2012 [21]3 years ago

8 0

Between 900 and 600 is 300 that is the answer

You might be interested in

Determine whether or not the following question can be considered as a statistical question.

aleksandr82 [10.1K]

Answer:. No

Step-by-step explanation:

Explanation:

The answer is NO because, mostly, there is always a variability in

the data used in answering statisticall questions. As in the question above, no variability

because Megan is taller than Jim or she is not taller than jim.

Thus, the question is not statistical in nature.

3 0

3 years ago

Read 2 more answers

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago

Juanita is 15 years old and her brother is 5. What is the ratio of Juanita's age to her brother's age?

eduard

15/5 = 3

hope this helps :)

5 0

3 years ago

Read 2 more answers

Please help I need to pass....

zzz [600]

Can you take a picture of the problem?

3 0

3 years ago

Mr. Marzano taught 150 students at the high school. The following year he started teach elementary students and had 22 students.

GenaCL600 [577]

Answer:

85%(estimated)

Step-by-step explanation:

150-22=128

changed ÷ original x 100%

128 ÷ 150 x 100%

≈ 85%

3 0

3 years ago