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2 years ago

If "x" is equal to 6, what is the value of the following expression? y = 2x + 9x + 3

Mathematics

1 answer:

ser-zykov [4K]2 years ago

3 0

Answer:

$y = 69$

Step-by-step explanation:

Given the following question:

$y=2x+9x+3$
$x=6$

Substitute and solve using PEMDAS:

$y=2x+9x+3$
$y=2(6)+9(6)+3$
$2\times6=12$
$y=12+9(6)+3$
$9\times6=54$
$y=12+54+3$
$12+54=66$
$66+3=69$
$y=69$

Your answer is "y = 69."

Hope this

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Factor completely 8x2-4x-84

mr_godi [17]

Answer: 4 • (2x - 7) • (x + 3)

Step-by-step explanation:

(4x+12)(2x-7)

8x²-28x+24x-84

8x²-4x-84

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2 years ago

PLS HELP ME 6, 7, and 8 (SHOW WORK!!) + LOTS OF POINTS + THANKS! + BRAINLIEST IF POSSIBLE!

julsineya [31]

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6 0

3 years ago

Read 2 more answers

g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d

professor190 [17]

Answer:

The variance and standard deviation of X are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - X) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable X is defined as, X = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

$P (X)=\frac{4}{20}=0.20$

A random sample of n = 3 items are selected at random.

The random variable X follows a Binomial distribution with parameters n = 3 and p = 0.20.

The variance of a Binomial distribution is:

$V(X)=np(1-p)$

Compute the variance of X as follows:

$V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48$

Compute the standard deviation (σ (X)) as follows:

$\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693$

Thus, the variance and standard deviation of X are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

$V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48$

Compute the standard deviation of (20 - X) as follows:

$\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693$

Thus, the variance and standard deviation of (20 - X) are 0.48 and 0.693 respectively.

3 0

2 years ago

If you divide any number by itself, what is the result? How can you apply this result to the expression -1×60/-1×10?

Alex73 [517]

Answer:

Step-by-step explanation:

Any number divided by itself is 1. In the expression-1 times -10 over -1 times -60 ,the -1s in the numerator and the denominator cancel each other out to give the result , or 6.

4 0

3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

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2 years ago