Answer: what would swimming in mathane lake on titan feel like.
Explanation:
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:
Finally, the resulting molarity in 30.8 mL (0.0308 L):
Regards.
96.09 g/mol good luck and give thanks:)
The balanced chemical reaction is written as:
<span>NaOH + HCl → NaCl + H2O
We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation.
2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O</span>
