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trapecia [35]
1 year ago
6

recall that temperature is a measure of the average kinetic energy of a substance. both ethanol and water had the same amount of

thermal energy added to them, but their temperatures are different. why does the same amount of added energy (in water) not increase its temperature as much as in ethanol?
Chemistry
1 answer:
Igoryamba1 year ago
8 0

The same amount of added energy in water not increase its temperature as much as in ethanol because of temperature difference.

What is temperature?
The physical concept of temperature expresses in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined various reference points as well as thermometric substances. The most popular scales are the Celsius scale, also known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), as well as the Kelvin scale (K), with the latter being primarily used for scientific purposes. One of the seven units inside the International System of Units is the kelvin (SI).

The average kinetic energy of all the atoms or molecules that make up a substance is how we define temperature in chemistry. A substance's constituent particles do not all possess the same kinetic energy. The distribution of the particles' kinetic energy at any particular moment can be used to describe it.

To learn more about temperature
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Use the term reclamation in a sentence
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If have a volume of 18 L of a gas at a temperature of 272 K and a pressure of 90 atm, what will be the pressure of the gas if ra
Solnce55 [7]

Answer:

P₂ ≅ 100 atm (1 sig. fig. based on the given value of P₁ = 90 atm)

Explanation:

Given:

P₁ = 90 atm                    P₂ = ?

V₁ = 18 Liters(L)              L₂ = 12 Liters(L)      

=> decrease volume => increase pressure

=> volume ratio that will increase 90 atm is (18L/12L)                                                                  

T₁ = 272 Kelvin(K)          T₂ = 274 Kelvin(K)

=>  increase temperature => increase pressure

=> temperature ratio that will increase 90 atm is (274K/272K)

n₁ = moles = constant    n₂ = n₁ = constant

P₂ = 90 atm x (18L/12L) x (274K/272K) = 135.9926471 atm (calculator)

By rule of sig. figs., the final answer should be rounded to an accuracy equal to the 'measured' data value having the least number of sig. figs. This means P₂ ≅ 100 atm based on the given value of P₁ = 90 atm.

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