Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
The equation that model a quadratic function is: y=0.9673x²-0.8475x+10.4334
Step-by-step explanation:
A quadratic function has the form of ;
f(x) = ax²+bx+c where a, b and c are real numbers and a≠0
For this case, equation y=0.9673x²-0.8475x+10.4334 models a quadratic function where a>0 thus the parabola opens upwards
See attached figure below to visualize the graph
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Quadratic functions graphs: brainly.com/question/9048896
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let h = horse, let c = cow, let p = pig
so,
hcp
hpc
cph
chp
phc
pch
so, that is 6 different ways she can arrange it.
Since triangle ABC is isosceles, then angles 1 and 9 are congruent.
4x + 3 = 9x - 47
-5x = -50
x = 10
m<1 = 4x + 3 = 40 + 3 = 43
m<1 = m<9 = 43
Triangle DBE is equilateral, so it is also equiangular.
m< 4 = m<5 = m<6 =60
Angles 3 and 8 are supplementary to congruent angles that measure 60 deg, so 180 - 60 = 120, so
m<3 = m<8 = 120
For angles 2 and 7, use the sum of the measures of the angles of a triangle is 180 deg.
m<1 + m<2 + m<3 = 180
43 + m<2 + 120 = 180
m<2 + 163 = 180
m<2 = 17
m<2 = m<7 = 17
