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3 years ago

If x = -2, which inequality is true?

Mathematics

2 answers:

Anettt [7]3 years ago

4 0

It’s J, 3 - X would equal 3 - (-2) which turns into 3+2 which equals 5 but 5 is not greater than 10

kaheart [24]3 years ago

4 0

Answer:

3 - x <10

Step-by-step explanation:

plug in -2 as x in each equation and see if its true

2(-2) + 6 < -1 -- false

2(-2) - 3 > 6 false

-5 + 3(-2) > 1 false

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Bubbles bakery has 24 oatmeal cookies, 36 vanilla bean cookies, 42 chocolate chip cookies. What is the greatest common factor bu

STatiana [176]

Answer:6

Step-by-step explanation:

We have three groups of cookies as follows:

24 oatmeal

36 vanilla bean

42 chocolate chip

If we breack down into factors we get

24 2 24 = 2³ * 3 36 2 36 = 2²*3³ 42 2 42 = 2*3*7

12 2 18 2 21 3

6 2 9 3 7 7

3 3 3 3 1

1 1

Fom where we can get that biggest common factor is 6

24 ÷ 6 = 4

36 ÷ 6 = 6

42 ÷ 6 = 7

Then Bakery will have 4 groups of oatmeal cookies, 6 of vanilla bean, and 7 chocolate chip

7 0

3 years ago

If a trader make a loss of 10% when he sells a watch for 15,300

puteri [66]

Answer:

A. original price: 16830

B. Profit gain: 918

10%=1530

6%=918

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4 0

3 years ago

Area of irregular figures<br><br> uhmmm

Ann [662]

Answer:

146

Step-by-step explanation:

4×12+5×10+4×12=146

3 0

2 years ago

The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did

Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

$P(A \, and \, B)= P(A)\times P(B\left | \right A )$

From the options, we have;

$P(fatigue \left | \right drug)$ = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)× $P(fatigue \left | \right drug)$

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

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3 years ago

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3 years ago