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lorasvet [3.4K]
3 years ago
8

16+ (-26) = -10 9.-16+(-4) - 16+(-4)= 12 3-(4)

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

The answer is -1.

Step-by-step explanation:

It is a little messy tho. I will assume that you want 3-(4)

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Can someone explain this to me pls
Maurinko [17]

Answer: 15 gallons are needed

Step-by-step explanation: Simplify the ratio 5:2, which is 2.5:1. Multiply 6 on both sides to get 15:6. :)

7 0
2 years ago
I need help with this one Eight cookies cost $12. At this rate, how much will 10 cookies cost?
mr Goodwill [35]

Answer:

$15

Step-by-step explanation:

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Which of the following is equivalent to the complex number i^8?
Maru [420]

Answer:

I think the answer is -1

Step-by-step explanation:

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4 0
2 years ago
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What is the inverse of the function y=x+5/7 ?
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8 0
3 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
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