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vivado [14]
3 years ago
6

The events committee buys 80 flowers for a school dance. The flowers are a combination of carnations and roses. Each carnation c

osts $0.50, and each rose costs $2.50. The committee spends a total of $72, not including tax.
How many of each type of flower does the committee buy?
Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

64 carnations and 16 roses.

Step-by-step explanation:

The events committee buys 80 flowers

The flowers are a combination of carnations and roses.

Each carnation costs $0.50 and each rose costs $2.50

The committee spends a total of $72

<u>Solution:</u>

<u />

Let there be  (c) carnations and (r) roses.

So,

c + r = 80 flowers

and $0.50c + $2.50 = $72

This forms a simultaneous equation:

c + r = 80 ... (i)

0.5c + 2.5r = 72 ... (ii)

Multiplying equation (i) by 0.5 and equation (ii) by 1 gives;

0.5c + 0.5r = 40 ... (i)

0.5c + 2.5r = 72 ... (ii)

Subtracting (i)  from (ii) gives;

0c + 2r = 32

2r = 32

r = 32 ÷ 2 = 16

Therefore, there are 16 roses

and 80 - 16 = 64 carnations

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Anastasy [175]

\huge\textsf{Hey there!}

\large\textsf{6!}\\\large\textsf{= 6}\times\large\textsf{5}\times\large\textsf{4}\times\large\textsf{3}\times\large\textsf{2}\times\large\textsf{1}\\\large\textsf{6(5) = \bf 30}\\\large\textsf{= 30}\times\large\textsf{4}\times\large\textsf{3}\times\large\textsf{2}\times\large\textsf{1}\\\large\textsf{30(4) = \bf  120}\\\large\textsf{= 120}\times\large\textsf{3}\times\large\textsf{2}\times\textsf{1}\\\large\textsf{120(3) = \bf 360}\\\large\textsf{= 360}\times\large\textsf{2}\times\large\textsf{1}

\large\textsf{360(2) = \bf 720}\\\large\textsf{720}\times\large\textsf{1}\\\large\textsf{= \bf 720}

\boxed{\boxed{\huge\textsf{Therefore, your answer is: \bf 720}\huge\textsf{ (option B)}}}\huge\checkmark

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4 0
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4 0
4 years ago
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