3 years ago

X-y=-3 Anyone know how to do this ?

1 answer:

7 0

X - y = -3

Move constant to the left by adding its opposite to both sides

x - y + 3 = -3 + 3

The sum of two opposites equals

your answer would be: x - y + 3 = 0

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P^-4q^3r^-7 over p^-2q^3p^-2 simplify

kondaur [170]

Answer:

$\large\boxed{r^{-7}=\dfrac{1}{r^7}}$

Step-by-step explanation:

$\dfrac{p^{-4}q^3r^{-7}}{p^{-2}q^3p^{-2}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=p^{-4-(-2)-(-2)}q^{3-3}r^{-7}\\\\=p^{-4+2+2}q^0r^{-7}\\\\=p^0q^0r^{-7}\\\\=r^{-7}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{r^7}$

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3 years ago

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Line segment AB is the diameter of circle C. If the endpoints of the diameter are (3, -4) and (7,2), what are the coordinates of

dimulka [17.4K]

Answer:

(5, -1)

Step-by-step explanation:

You find the center of both the coordinates. For the x axis: 3+7 = 10. 10/5=2. For the y axis: -4+2=-2. -2/2 = -1. Put them together and get the answer! :)

5 0

3 years ago

Consider this sequence

pochemuha

Hello,

$u_{1} =1*(8-7)=1*(2*4-(6+1))\\
 u_{2} =2*(10-7)=2*(2*5-(6+2))=2*(2*(4+1)-(6+2))\\
 u_{3} =3*(12-9)=3*(2*6-(6+3))=3*(2*(4+2)-(6+3))\\
 u_{4} =4*(14-10)=4*(2*7-(6+4))=4*(2*(4+3)-(6+4))\\

$

$u_{10}=10*(2*(4+10)-(6+10))\\
=10*(28-16)
$

$...\\\\
u_{n} =n*(2*(n+n-1)-(6+n))\\
=n*(4n-2-6-n)=n(3n-8)\\

$

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3 years ago

What is 140/180 as a decimal

Naddika [18.5K]

I think the answer is 0.8 or 0.78.
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You can either round up to the nearest hundredth or tenth.

7 0

3 years ago

Helpppp me plz i dont get it

SOVA2 [1]

Try 3.14x2= 6.28 im so sorry if its wrong

6 0

3 years ago

Read 2 more answers