Suppose that a particle following the given path c(t) flies off on a tangent at t = t0. Compute the position of the particle at
the given time t1. c(t) = (2t2, t3 − 4t, 0), where t0 = 3, t1 = 4
1 answer:
Answer:
(30,35,0)
Step-by-step explanation:
We are given that


The velocity of particle,
Substitute 


The tangent line at t=3 is given by

Now, substitute t=4


Hence, the position of particle at
=(30,35,0)
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