Repetition structures, or loops, are used when a program needs to repeatedly process one or more instructions until some condition is met, at which time the loop ends. Many programming tasks are repetitive, having little variation from one item to the next. Vectorized mathematical code appears more like the mathematical expressions found in textbooks, making the code easier to understand. That is the difference. Hope I could help you on Brainly.com!
I think it would be False. Because its not only certain computers that can connect to the internet & send/receive messages, its any device that has access to it. Hope this helps! =^-^=
Answer:
Check the explanation
Explanation:
we will be writing the below codes in answering the question above.
The Code:
name="Tony stark"
firstname=name[0:4]
lastname=name[5:]
print(firstname,lastname) #first one
print(len(firstname)) #second one
s='s'
p='p'
i='i'
result='m'+i+(s*2+i)*2+p*2+i #third one
print(result)
The output can be seen in the image below.
There are 2n possible bit strings for any n.
<h3>What makes something a palindrome?</h3>
- The way they read both forward and backward is the same.
- A palindrome is a word, phrase, or sentence that reads the same both forward and backward.
- Palindrome is a combination of the Greek words for "again" (Palin) and "to run" (drom).
- A palindromic number, sometimes referred to as a numeral palindrome or a numeric palindrome, is one whose value does not change when its digits are flipped, for example, 16461.
- The single palindrome date in the M/DD/YYYY date format in 2022 is February 20, 2022. (2-20-2022)
To learn more about palindrome, refer to:
brainly.com/question/28279486
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To answer this, lets run through the code:
<span>ArrayList bulbs = new ArrayList(); //create a new empty list
bulbs.add(new Light()); //size of bulbs = 1
bulbs.remove(0); //remove item at index 0. size of bulbs = 0
bulbs.add(new Light()); // size of bulbs = 1
Light b = new Light();
bulbs.add(1, b); // size of bulbs = 2
bulbs.add(new Light()); //size of bulbs = 3
bulbs.remove(0); //remove bulb at index 0. Size of bulbs = 2
bulbs.add(new Light()); size of bulbs = 3
bulbs.remove(2); //remove bulb at index 2. size of bulbs = 2
bulbs.add(new Light()); //size of bulbs = 3
bulbs.add(1, new Light()); //inserted at position 1. size of bulbs = 4
The final answer. Size of bulbs = 4.</span>