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2 years ago

A bicycle shop advertised all mountain bikes priced at 1/3 discount.

2 answers:

6 0

327/3=$107 so the cost of the discounted mountain bikes are $107. The discounts subtract $214. I think im a lil confused on the question

Talja [164]2 years ago

4 0

Answer:

a. 109$

b. 327/3= 109

you're welcome

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A repair person is scheduled to be at your apartment between 9:00am to 12:00pm but you have to leave at 11:30 to help out a frie

sergiy2304 [10]

<h3>Answer:</h3>

5/6

<h3>Explanation:</h3>

There are 6 half-hours between 9 and 12. You will be there for 5 of them. The probability you will be there is 5/6.

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2 years ago

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2 years ago

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2 years ago

Benjamin walks 11/15 miles to work and then 3/10 miles to the grocery store how far does he walk

melamori03 [73]

Answer:31/30

Step-by-step explanation:

11/15+3/10

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2 years ago

If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H

vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that $2^n + 1$ is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that $p\mid n$ . Then, for some integer $k\geq 1$ ,

$n=p\times k.$

Therefore

$2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.$

Here we will use the formula for the sum of odd powers, which states that, for $a,b\in \mathbb{R}$ and an odd positive number $n$ ,

$a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})$

Applying this formula in 1) we obtain that

$2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1)$ .

Then, as $2^k+1>1$ we have that $2^n+1$ is not a prime number, which is a contradiction.

In conclusion, if $2^n+1$ is an odd prime, then n must be a power of 2.

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2 years ago