Answer:
5.92
Step-by-step explanation:
16*37=
592
put the decimals in next
Answer:
Step-by-step explanation:
the first one
Answer:
<em>C(19)=12 responses</em>
Step-by-step explanation:
<u>Exponential Decay Function</u>
The exponential function is frequently used to model natural growing or decaying processes, where the change is proportional to the actual quantity.
An exponential decaying function can be expressed as follows:

Where:
C(t) is the actual value of the function at time t
Co is the initial value of C at t=0
r is the decaying rate, expressed in decimal
The company puts out an advertisement for a job opening. Initially, the company got 90 responses to the advertisement. Each day, the responses declined by 10%.
This is an example where the decay model can be used to calculate the responses to the advertisement at the day t.
The initial value is Co=90, the decaying rate is r=10% = 0.10. The model is written as:

Calculating:

We are required to calculate the number of responses at day t=19, thus:

C(19)=12 responses
I would say number 2 but dont take my word for it
Answer:
Step-by-step explanation:
This is an exponential equation that is solved by taking the natural log of both sides. The equation is

If we are looking for x when f(x) = 64, then

Take the natural log of both sides:

The rules of logs allows us to bring the x down in front:

Divide both sides by ln(2) to get:

Do this on your calculator to get that x = 6.
You could also have just gone right to your calculator and started raising 2 to consecutive powers starting at like 3 or 4 to eventually get that 2 to the 6th power is equal to 64, but for the basics of solving log equations, you need to know how to do this.