z^2+4zy+4y^2 What is this completely factored?
1 answer:
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we know that
If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation
we have the equation
Let's verify all the cases to determine the solution to the problem.
<u>case A)</u> point
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case B)</u> point
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case C)</u> point
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
<u>case D)</u> point
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
therefore
<u>the answer is </u>