All categories

2 years ago

What is the DOMAIN of the following relation? {(-5,4), (-4,2), (0,2), (1,3), (2,4)}

Mathematics

2 answers:

weeeeeb [17]2 years ago

3 0

Answer:

{-5, -4, 0, 1, 2}

Step-by-step explanation:

The domain is the inputs or the x values

{-5, -4, 0, 1, 2}

Vilka [71]2 years ago

3 0

Answer:

See below.

Step-by-step explanation:

The domain of a relation is all of the x-coordinates.

So we have the relation:

{(-5,4), (-4,2), (0,2), (1,3), (2,4)}

This means that the domain will be the following values:

{(-5,4), (-4,2), (0,2), (1,3), (2,4)}

So, our domain is:

$\{-5, -4, 0, 1, 2\}$

Note that the domain is in ascending order.

You might be interested in

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

2 years ago

Which congruence postulate proves that the two triangles are<br> congruent?

inna [77]

The answer is SSS since both triangles have equal sides the third one has to be congruent since they share the same line

8 0

3 years ago

How to solve 10(x+4)(x-4)

IceJOKER [234]

Answer:

1 Use Difference of Squares:

a^2-b^2=(a+b)(a−b).

10(x^2-4^2)

2 Simplify 4^2 to 16

10(x^2 −16)

3 Expand by distributing terms.

10x^2 −160

Step-by-step explanation:

Hope dis helps and pls mark me as brainlist!!!

§ALEX§

4 0

3 years ago

How can i get the volume??

Paladinen [302]

Length times width times height gives you the volume of things

6 0

3 years ago

If a dog is running 25 feet per second, how far will he travel after 1 minute of running?

PIT_PIT [208]

Answer:

1500 feet

Step-by-step explanation:

In 1 sec= 25 feet

In 1 minute= 60 seconds= 25*60 feet

= 1500 feet.

8 0

2 years ago

Read 2 more answers