Jane did not show factors of 8, she showed multiples of 8. Factors of 8 would be 1, 2, 4, and 8
No it is not because for the x value of 5 there are two different y values.
Area = 4x(2x + 3) = 8x2 + 12x
Perimeter = 2(2x + 3 + 4x) = 12x + 6
A. x = 7, y = 4, z = 3
How?
Just plug in the numbers.
7 + 4 + 3 = 14
11 + 3 = 14
14 = 14
Next.
4 + 3 = 7
Next.
3 = 3
