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uysha [10]
3 years ago
13

A petri dish of bacteria grow continuously at a rate of 200% each day. If the petri dish began

Mathematics
1 answer:
Molodets [167]3 years ago
4 0

Answer: 2430 bacteria.

Step-by-step explanation:

When we have a quantity A, and we have an increase of the X%, the new quantity can be written as:

A + (X%/100%)*A

In this case, we have A = 10 bacteria.

And X% = 200%.

Then if we start with 10 bacteria.

After one day, we will have:

10 bacteria  + (200%/100%)*10 bacteria

= 10 bacteria + 2*10 bacteria = 3*10 bacteria.

After another day, we will have:

3*10 bacteria + (200%/100%)*(3*10 bacteria)

3*10 bacteria  + 2*(3*10 bacteria)

3*(3*10 bacteria)

10 bacteria*(3)^2

We already can see the pattern here.

After t days, we will have:

10 bacteria*(3)^t.

This is the equation f(t) we wanted:

f(t) =10 bacteria*(3)^t

after 5 days, we will have:

f(5) = 10 bacteria*(3)^5 = 2430 bacteria.

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Help please!! really quickly
yKpoI14uk [10]

y =  \frac{7}{5} x + 1
8 0
3 years ago
find the smallest number of terms of the AP "-54,-52.5,-51,-49.5" ....that must be taken for the sum of the terms to be positive
wel

The smallest number of terms of the AP that will make the sum of terms positive is 73.

Since we need to know the number for the sum of terms, we find the sum of terms of the AP

<h3>Sum of terms of an AP</h3>

The sum of terms of an AP is given by S = n/2[2a + (n - 1)d] where

  • n = number of terms,
  • a = first term and
  • d = common difference

Since we have the AP "-54,-52.5,-51,-49.5" ....", the first term, a = -54 and the second term, a₂ = -52.5.

The common difference, d = a₂ - a

= -52.5 - (-54)

= -52.5 + 54

= 1.5

<h3>Number of terms for the Sum of terms to be positive</h3>

Since we require the sum of terms , S to be positive for a given number of terms, n.

So, S ≥ 0

n/2[2a + (n - 1)d] ≥ 0

So, substituting the values of the variables into the equation, we have

n/2[2(-54) + (n - 1) × 1.5] ≥ 0

n/2[-108 + 1.5n - 1.5] ≥ 0

n/2[1.5n - 109.5] ≥ 0

n[1.5n - 109.5] ≥ 0

So, n ≥ 0 or 1.5n - 109.5 ≥ 0

n ≥ 0 or 1.5n ≥ 109.5

n ≥ 0 or n ≥ 109.5/1.5

n ≥ 0 or n ≥ 73

Since n > 0, the minimum value of n is 73.

So, the smallest number of terms of the AP that will make the sum of terms positive is 73.

Learn more about sum of terms of an AP here:

brainly.com/question/24579279

#SPJ1

4 0
2 years ago
Write the expression in simplest form:<br><br> 5n - 6 + n - 1
nata0808 [166]
To write this equation in simplest form, we simply need to combine all like terms. The like terms in this particular expression are the terms with an n-variable and the terms with no variable. So we can combine them to simplify our expression.

5n - 6 + n - 1

First step, we can reorder our terms so that like terms are near each other

5n + n - 6 - 1

Now we can combine easily

(5n + n) - (6 - 1)

6n - 5

And that is your simplified expression.

5n - 6 + n - 1 in simplest form is 6n - 5.
Hope that helped! =)
4 0
3 years ago
1. If OQ and RT are parallel lines which statement is true?
Kaylis [27]

Answer:

Step-by-step explanation:

Question (1).

OQ and RT are the parallel lines and UN is a transversal intersecting these lines at two different points P and S.

A). ∠OPS ≅ ∠RSU [corresponding angles]

B). m∠OPS + m∠RSP = 180° [Consecutive interior angles]

C). m∠OPS + m∠OPN = 180° [Linear pair of angles]

D). Since, ∠OPS ≅ ∠TSP [Alternate interior angles]

    And m∠TSP + m∠TSU = 180° [Linear pair of angles]

Therefore, Option (A) is the correct option.

Question (2).

A). m∠RSP + m∠RSU = 180° [Linear pair of angles]

B). m∠RSP + m∠PST = 180° [Linear pair of angles]

C). ∠RSP ≅ ∠TSU [Vertically opposite angles]

D). m∠RSP + m∠OPS = 180° [Consecutive interior angles]

Therefore, Option (C) will be the answer.

3 0
3 years ago
Read 2 more answers
19. Find the slope of the line graphed below.
Furkat [3]

Answer:

I think it's 19/12

Step-by-step explanation:

the left point is 11,-6

the right point is -8,6

11+8=19

6+6=12

rise over run or y/x

19/12

I don't think it can be simplified if I'm wrong I'm really sorry :T

7 0
3 years ago
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