SWITCH BETWEEN OPEN PRESENTATIONS. ..... Presentation software is a program designed for the production and display of .... image file format and version number. 1. .... Option. To Do This. Normal. Contains three panes: the outline pane, the slide pane, and the notes pane. .... appear on every slide in a presentation.
<u> C++ Program to Print Pascal's Triangle</u>
#include<iostream>
//header file
using namespace std;
//driver function
int main()
{
int r;/*declaring r for Number of rows*/
cout << "Enter the number of rows : ";
cin >> r;
cout << endl;
for (int a = 0; a < r; a++)
{
int value = 1;
for (int b = 1; b < (r - a); b++)
/*Printing the indentation space*/
{
cout << " ";
}
for (int c = 0; c <= a; c++)
/*Finding value of binomial coefficient*/
{
cout << " " << value;
value = value * (a - c) / (c + 1);
}
cout << endl << endl;
}
cout << endl;
return 0;
}
<u>Output</u>
<u>Enter the number of rows : 5</u>
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
Answer:
The purpose of supply chain management is
On the most basic level, the purpose of supply chain management is to make inventory readily available in customer facing positions to fulfill demand. ... Supply chain partners must work together to maximize resource productivity, develop standardized processes, eliminate duplicate efforts, and minimize inventory levels
Explanation:
Answer: D) Content creator
Explanation:
- Content creator are responsible for creating the original content of the website. They contribute writing the blog posts about various topics and promote the content with the help of digital and social media.
- Content creator are basically responsible for writing blog post on the industry based topics, graphic design and video editing.
Content editor uses data and evaluation from the users for analysis. It basically includes design and development to enhanced the material on the website.
Static and dynamic information are related to computer terminologies.
Therefore, (D) option is correct.
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
