8x-6y=-96 add to this -4 times the second equation...
-8x-12y=-48
___________
-18y=-144
y=8, this makes 8x-6y=-96 become:
8x-48=-96
8x=-48
x=-6
so the solution to the system of equations is the point:
(-6,8)
Answer:
Step-by-step explanation:
m∠1=m∠3
m∠2=m∠4
3*(m∠1+m∠3)=m∠2+m∠4
3*(m∠1+m∠1)=m∠2+m∠2
3×2 m∠1=2 m∠2
m∠2=3 m∠1
now m∠1+m∠2=180°
m∠1+3 m ∠1=180
4 m∠1=180
m∠1=180/4=45°
m∠3=45°
m∠2=180-m∠1=180-45=135°
m∠4=135°
B(cone)=B(pyramid)=r²π
V(pyramid)=1/3 * B * H = 1/3 * r² π * 3 r ( 3 will cancel out )= r³ π
Answer: r³ π
Are you looking for slope?
if u r the slope is -6/3
The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).


Therefore, 

t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :

= 0.020908803
The p value is 0.0209

So we reject the null hypothesis and conclude that 