This is the concept of simultaneous equations, the question requires us to solve the system of equations given by:
2x+4y=38
10x+3y=105
from the top equation;
2x=38-4y
dividing through by 2 we get:
x=19-2y......(*)
substituting (*) in the second equation we get:
10x+3y=105
10(19-2y)+3y=105
190-20y+3y=105
collecting like terms we get:
-20y+3y=105-190
-17y=-85
dividing both sides by -17 we get:
(-17y)/(-17)=(-85)/(-17)
y=5
thus
x=19-2y
x=19-2*5
x=19-10
x=9
thus
x=9 and y=5
Because the 2 triangles are similar, find the ratio of 2 known sides.
Side XY = 10
Side AB = 25
25 / 10 = 2.5
This means the larger triangle is 2.5 times larger than the smaller one.
Now find the side of the smaller triangle, that would be the same side as X on the larger triangle and multiply that by 2.5.
XZ is the same side as AC
So X = 6 x 2.5
X = 15
Trying to get 3:1
Divide 236 by four=59
Then times 59 by 3
The ratio now is 177:59
3:1
Answer:
150:200
Step-by-step explanation:
You can simplify it too. 3:4
