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3 years ago

Determine the Decreasing Intervals of the Piecewise Defined Function:

Mathematics

1 answer:

Hitman42 [59]3 years ago

8 0

I’m so sorry like very sorry

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3 times a number increased by 4 is less than -62

grigory [225]

3n+4<-62

n being the number
+4 for the number being increased by 4.
3n=3*n
< the less than sign

Hope this helped!

6 0

3 years ago

Square root of 64 by division method

weeeeeb [17]

hope you understand.....

6 0

3 years ago

Please help! I have 35 minutes left! You can get 100 points!

Stella [2.4K]

Answer:

The expression equivalent to 8 - (6r + 2) is -6r + 6 ⇒ A

Step-by-step explanation:

Let us solve the question

∵ The expression is 8 - (6r + 2)

→ Multiply the bracket by (-)

∵ (-) × (+) = (-)

∴ 8 - (6r + 2) = 8 - 6r - 2

→ Add the like terms

∵ 8 - (6r + 2) = (8 - 2) - 6r

∴ 8 - (6r + 2) = 6 - 6r

→ Switch the terms

∴ 8 - (6r + 2) = -6r + 6

∴ The expression equivalent to 8 - (6r + 2) is -6r + 6

7 0

4 years ago

Which choice is equivalent to the quotient below? sqrt 7/8* sqrt7/187/16/121/23/47/12

mario62 [17]

We can apply the following properties of radicals:

$\begin{gathered} \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\Rightarrow\text{ Product property} \\ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}\Rightarrow\text{ Quotient property} \end{gathered}$

Then, we have:

$\begin{gathered} \text{ Apply the product property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7}{8}\cdot\frac{7}{18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7\cdot7}{8\cdot18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{49}{144}} \\ \text{ Apply the quotient property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{\sqrt[]{49}}{\sqrt[]{144}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{7}{12} \end{gathered}$

Therefore, the choice that is equivalent to the given product is:

$\frac{7}{12}$

4 0

1 year ago

Which statement is true about the square pyramid below?

Reika [66]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers