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balandron [24]
3 years ago
9

Help please thanks math is hard

Mathematics
1 answer:
leonid [27]3 years ago
8 0
X= 25
Explanation:
The two lines are equal. Since 48+16= 64,
the other line has to equal 64 as well.
64-39= 25
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50 points Its really geometry Distance Formula
scoray [572]

Step-by-step explanation:

1) 51

2)32

3) 18

4)9

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3 years ago
M<br> Hurry answer it’s due today
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Answer:

83.55

Step-by-step explanation:

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5 0
3 years ago
If M is the midpoint of AB, find the coordinates of A if M(-3, 5) and B(6, -11)
Luden [163]

midpoint= (x, y)

where x=(x1 + x2)/2

y=(y1 + y2)/2

x1=-3, x2=6, y1=5, y2=-11

so x=(-3 + 6)/2= 3/2

y=(5 + -11)/2= (5-11)/2= -6/2= -3

so mid point =(3/2, -3)

hope this helps

7 0
3 years ago
Write the linear equation that gives the rule for this table.
Zinaida [17]

Answer:

f(x) = -7x + 1

Step-by-step explanation:

Slope intercept form is

y = mx + b

m is slope

b is y-intercept

--------------------------

y decreases by 7 for each increase of 1 in x

slope = -7

to find "b" plug in one of the points and m = -7

using point (3, -20)

y = mx + b

-20 = -7(3) + b

-20 = -21 + b

b = 1

The equation is

f(x) = -7x + 1

3 0
3 years ago
What are the solutions of 3x2 + 14x + 16 = 0?
Leya [2.2K]

Answer:

Given the equation: 3x^2+14x+16=0

The general equation of quadratic formula for ax^2+bx+c=0 where a, b and c are constant;

then, the solution for this equation  is given by;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}              ......[1]

From the equation, 3x^2+14x+16=0 we have

a =2, b=14 and c=16

Substitute these values in [1] to solve for x;

&#10;x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}              

or

x=\frac{-14\pm\sqrt{196-192}}{6} =\frac{-14\pm\sqrt{4}}{6}

Simplify:

x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}

then,

x=\frac{-14+2}{6} =\frac{-12}{6} =-2 and

x=\frac{-14-2}{6} =\frac{-16}{6} =\frac{-8}{3}

Therefore, the solutions for the given equation is; x =-2 and x =-\frac{8}{3}



6 0
4 years ago
Read 2 more answers
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