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3 years ago

6

Waygate's residential Internet modem works well but is sensitive to power-line fluctuations. On average, this product hangs up a

nd needs resetting every 200 hours. On average about 45 minutes is needed to reset this product. What is this product's availability

Computers and Technology

1 answer:

dalvyx [7]3 years ago

3 0

Answer:

The answer is "In excess of 0.95 "

Explanation:

$MTBF= 200\ hours (12,000\ minutes)\\\\MTR= 45\ minutes (0.75\ hours)$

Availability equation $=\frac{ MTBF}{(MTBF+MTR)}$

Calculating the minutes as the common units:

$= \frac{12,000}{(12,000+45)}\\\\= \frac{12,000}{(12,045)}\\\\= 0.9962\\\\= In\ excess\ of\ 0.95$

Calculating the hours as the common units:

$= \frac{200}{(200+0.75)}\\\\= \frac{200}{200.75}\\\\= 0.9962\\\\= In \ excess\ of\ 0.95$

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Drag each statement to the correct location.

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Answer:

$(a)\ 222_{10} = DE_{16}$ --- True

$(b)\ D7_{16} = 11010011_2$ --- False

$(c)\ 13_{16} = 19_{10}$ --- True

Explanation:

Required

Determine if the statements are true or not.

$(a)\ 222_{10} = DE_{16}$

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

$DE_{16} = D * 16^1 + E * 16^0$

In hexadecimal.

$D =13 \\E = 14$

So, we have:

$DE_{16} = 13 * 16^1 + 14 * 16^0$

$DE_{16} = 222_{10}$

Hence:

(a) is true

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First, convert D7 to base 10 using product rule

$D7_{16} = D * 16^1 + 7 * 16^0$

$D = 13$

So, we have:

$D7_{16} = 13 * 16^1 + 7 * 16^0$

$D7_{16} = 215_{10}$

Next convert 215 to base 2, using division rule

$215 / 2 = 107 R 1$

$107/2 =53 R 1$

$53/2 =26 R1$

$26/2 = 13 R 0$

$13/2 = 6 R 1$

$6/2 = 3 R 0$

$3/2 = 1 R 1$

$1/2 = 0 R1$

Write the remainders from bottom to top.

$D7_{16} = 11010111_2$

<em>Hence (b) is false</em>

$(c)\ 13_{16} = 19_{10}$

Convert 13 to base 10 using product rule

$13_{16} = 1 * 16^1 + 3 * 16^0$

$13_{16} = 19$

Hence; (c) is true

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