4(3x-1)=9-x Thank you !

denpristay [2]

Answer:

3,524 corresponde al fraccionario $\frac{3524}{1000}$ .

Step-by-step explanation:

La coma está desplazada tres espacios (3 dìgitos) hacia la izquierda del observador, el número decimal tiene su equivalente forma fraccionaria, en donde el numerador son todos los dìgitos en series y el denominado tiene la forma 10ⁿ, donde n es la cantidad de espacios que ha sido desplazada la coma. Entonces, 3,524 tiene la siguiente expresión:

$3,524 = \frac{3524}{10^{3}}$

$3,524 = \frac{3524}{1000}$

3,524 corresponde al fraccionario $\frac{3524}{1000}$ .

5 0

3 years ago

1. Emily filled an empty horse trough with water. The water level, in centimeters, is proportional to time elapsed, in minutes,

Pie

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
depth of water is proportional to time
d = k*t
d = 7/2 * t 
a) the point (2,28) represents the rate 28/8 
b) 3.5 cm/sec
c) the slope between (8, 28) and (6, 21) is 7/2 = 3.5

3 0

3 years ago

Please help I dont get it 20 points

Klio2033 [76]

Answer:

10

Step-by-step explanation:

P(getting blue marbles) = 7/9

so;

x/45 = 7/9

x = 35

so the number of blue marbles is 35

45 - 35 = 10 red marbles

hope it helps .

all the best

4 0

3 years ago

Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?

monitta

Answer:

$(x-7)^2+(y-2)^2=34$

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (7, 2), h = 7 and k = 2. Substitute:

$(x-7)^2+(y-2)^2=r^2$

Next, the since a point on the circle is (2, 5), y = 5 when x = 2. Substitute:

$(2-7)^2+(5-2)^2=r^2$

Solve for r:

$(-5)^2+(3)^2=r^2$

Simplify. Thus:

$25+9=r^2$

Finally, add:

$r^2=34$

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

$(x-7)^2+(y-2)^2=34$

4 0

3 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

3 years ago