1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
3 years ago
13

Greta read a 900 pages book in 15 days, reading for 5 hours every day. How many pages did she read per hour

Mathematics
1 answer:
allsm [11]3 years ago
8 0
First, let's find how many page's Greta read per day. She read a total of 900 pages across 15 days, so she read:

900 pages / 15 days = 60 pages/day

Now we can find how many pages she read per hour by dividing the 60 pages per day by 5 hours:

60 / 5 = 12 pages/hour

The answer is 12 pages.
You might be interested in
Which logorithmic equation is equivalent to the exponential equation below? e^a=60
Alex73 [517]

Answer:

a = ln(60)

Step-by-step explanation:

4 0
2 years ago
The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This dist
alexira [117]
<h3>Answer:   83.85%</h3>

This value is approximate.

==========================================================

Explanation:

Let's compute the z score for x = 40

z = (x-mu)/sigma

z = (40-47)/7

z = -1

We're exactly one standard deviation below the mean.

Repeat these steps for x = 68

z = (x-mu)/sigma

z = (68-47)/7

z = 3

This score is exactly three standard deviations above the mean.

Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.

34+34+13.5+2.35 = 83.85

<u>Roughly 83.85%</u> of the one-mile roadways have between 40 and 68 potholes.

5 0
2 years ago
50 POINTS
mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A:

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet  at a rate of 7.5 ft/s

Part B:

Between 2 and 4 seconds, the height stays constant at 75 feet.

Part C:

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s

Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.

Part D:

From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.

3 0
3 years ago
7<br> Solve the equation x^2 - 8x + 15 = 0.
Oksanka [162]

Answer:

x=5   x=3

Step-by-step explanation:

x^2 - 8x + 15 = 0

Factor

What 2 numbers multiply to 15 and add to -8

-5*-3 = 15

-5-3 = -8

(x-5)(x-3) =0

Using the zero product property

x-5 =0    x-3 =0

x=5   x=3

3 0
3 years ago
Read 2 more answers
Those who have taken the Algebra EOC please answer.
Dennis_Churaev [7]

Step-by-step explanation:

To me yes.

Algebra is mostly memorization. If you know the formulas and know how to apply it, you should do good.

I say use this. Algebra topics are like building on top each other.

Heart of Algebra:

  • Review what the purpose of x in algebra.
  • Then learn things like combining like terms, and solving for x.
  • Since you know the basics of x, you can then review linear equations( imo, a big content of algebra). Stuff like slope, different linear forms, graphs of linear equations, and mostly linear equation word problems
  • Then you can review system of equations. since you know how to manipulate linear equations, etc.

Then move on to other algebra topics dealing with algebra like

  • functions, and different types of them
  • exponents, and radicals rules
  • inequalities.
  • sequences.
  • These aren't the heart of algebra but study them they are useful and it important to know them.

Since you learned different function rules, we can move on to learning exponetial functions, graphs, and word problems.

Then finally, learn most hard thing in Algebra: Quadratics.

Pratice,practice, and practice and you will pass.

Try to memorize the formulas and know when to apply it.

Good Luck

7 0
2 years ago
Other questions:
  • True or false
    9·1 answer
  • Help needed! Due by 6/22/19
    11·1 answer
  • The owner of Ray’s Deli wants to find out if there is a relationship between the temperature in summer and the number of glasses
    5·2 answers
  • Which expression is 7 times as large as the expression 596+88.
    11·2 answers
  • Find the angel x in d diagram above with a well structured solution.<br><br>Thanks​
    5·1 answer
  • PLEASE HELPP!!!!!! FOR 10 POINTS. Am I right? Show work if I’m wrong
    5·2 answers
  • Find the y-intercept for the following function: 3x-4y=12
    11·2 answers
  • Convert 0.00425 into scientific notation 
    5·1 answer
  • Twenty minutes to six in the evening on a 24 hour clock​
    14·1 answer
  • Which expression is not equivalent to the other three? 2x 2 2x 3x – 8 4 7x – 2 –2 5x 2x – 4 8x – x – 6.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!