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3 years ago

Chef Selena is making her special dish that requires pasta, sauce, and onions.

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

A and D. She can make 32 servings in total.

Step-by-step explanation:

This is because if she were to mix up all of the products, she would have 16 pounds of mix in total.

5 1/8 + 4 7/8 + 6 = 16

This is choice A.

Then she must divide this by 1/2 because each serving is 1/2 pound.

16 ÷ 1/2 = 32

That is choice D.

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ing needs 3 cups of milk to make 30 cookies. How many ounces of milk would he need to make 120 cookies?

Llana [10]

Answer:

12 cup of milk.

Step-by-step explanation:

if 3 cups of milk can make 30 cookies it means 1 cup of milk can make 10 cookies then for 100 cookies we need 10 cup of milk and 30 more means 3 more so answer is 12

8 0

3 years ago

Multiply. Express your answer in standard form.(x^2-4x+3)(-3x^2+7x-1)

Yakvenalex [24]

Answer:

-3x^4 + 5x^3 - 33x^2 + 25x - 3

//Hope it helps and it's right.

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3 years ago

Can I get a help please

iogann1982 [59]

Answer:

middle graph

Step-by-step explanation:

Soluton

The second (middle ) graph is the only one that works.

First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ - 1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.

6 0

1 year ago

Help me right now like now

Reika [66]

Answer:

2. trust me.. i did it before.

4 0

2 years ago

Read 2 more answers

Math again yay!...Ew math

Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

$f(x)=x^2$

New function:

$g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2$

Transformations:

For a > 0

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}$

$\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}$