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Allushta [10]
3 years ago
7

What is the prime factorization of 33

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
The answer is 11 and 3
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Solve the linear equations of 2x - y = 4<br> 1 - 3y = -3<br> Please I’m in the middle of a test help
lesantik [10]

Answer:

x = \frac{8}{3}, y = \frac{4}{3}

Step-by-step explanation:

Solve for  y  in the first equation.

y=\frac{4}{3}, replace y with \frac{4}{3}

Solve for in the first equation.

x = \frac{8}{3}, y = \frac{4}{3}

<em>good luck, hope this helps :)</em>

3 0
3 years ago
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Leroi and Sylvia both put $100 in a savings account. Leroi decides he will put in an additional $10 each week. Sylvia decides to
kati45 [8]
Leroi’s account

$100
After first deposit = $100+$10=$110
After second deposit= $110 + $10 = $120


Sylvia’s account

$100
10% of $100 is $10
After first deposit = $100+ $10 = $110
10% of $110 = $11
After second deposit = $110 + $11 = $121

Therefore after their first deposit, both will have the same value in their accounts.
But after the second deposit, Sylvia will have 1$ more in her account than Leroi.
7 0
3 years ago
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Quadrilateral ABCD is located at A(-2,2), B(-2,4) and D(2,2). The quadrilateral is then transformed using the rule (x+2,y-3) to
Kay [80]
The rule is x+2, y-3 so you apply it to each of these coordinates. Right 2, down 3.
A(-2,2) -> A'(0,-1)
B(-2,4) -> B'(0, 1)
D(2,2) -> D'(4,-1)
7 0
4 years ago
Equation for a circle with a diameter that has endpoints at (2, –5) and (8, –9)
chubhunter [2.5K]

The standard form for the equation of a circle is :

<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :

 ((2+(8))/2,(-5+(-9))/2)=(5,-7)

 So the point (5,-7) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(2−(5))^2+(-5−(-7))^2=9+4=13

 ⇒r=√13

 Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :

 (x-5)^2+(y+7)^2=13

5 0
4 years ago
A person creates a game in which a person pays $5.00 to play. Then, they draw a single card from a standard
Andrew [12]

Answer:

Step-by-step explanation:

$5.00

7 0
4 years ago
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