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masha68 [24]
3 years ago
13

David is selling floral arrangements. Each arrangement uses 1 vase and 12 roses. Each vase costs David $2.00. Let C be the total

cost of the arrangement and r be the cost of 1 rose. Which equation should David use to find the total cost of each arrangement? C = 12r + 2 12 = C + 2r C = 2r + 12 12C = r + 12
Mathematics
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

<h2>C = 12r + 2</h2>

Step-by-step explanation:

To model the equation for the cost of Each Arrangement.

We need to itemize all parameters needed.

An arrangement consists of

1. one vase

2. twelve roses

Given that 1 vase cost $2 and

The cost of one rose is r

Let the total cost of the arrangement be C

Hence C is the  cost of the vase plus the cost of 12 roses combined, this is given as

C = 12r + 2

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beks73 [17]

Answer:

The Value of a=\frac{15}{4}.

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

sin\ \theta = \frac{opposite\ side}{Hypotenuse}

sin \ S= \frac{PQ}{QS}

Substituting the given values we get;

sin\ 30\°=\frac{x}{15}

Now we know that;

sin\ 30\° = \frac12

So we can say that;

\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\

Cos\ Q = \frac{QR}{PQ}

Substituting the given values we get;

cos 60\°= \frac{a}{x}

Now we know that;

cos 60\°= \frac12

x=\frac{15}{2}

So substituting the values we get;

\frac{1}{2}=\frac{a}{\frac{15}{2}}

By Using Cross Multiplication we get;

a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}

Hence The Value of a=\frac{15}{4}.

6 0
3 years ago
Please help I will mark Brainly
Sedbober [7]
The answer for your question is 686
8 0
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Step-by-step explanation:

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Step-by-step explanation:

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F the point (a, 7) lies on the graph of the equation 5x - y = 8, then a=
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(a,7) lies on the equation of 5x-y=8, that means we solve for x when y=7.

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