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DerKrebs [107]
4 years ago
8

Just the equation, i have difficulty with word problems & need some help

Mathematics
1 answer:
Brut [27]4 years ago
4 0
At rate x miles/ hour drove d miles/ 4 hours;
At rate x-10 miles / hour drove d miles/5 h

d miles = x• 4 miles first rate
d miles= (x-10)•5 miles second rate

5x-50= 4x
5x-4x= 50
X= 50 miles/h to get to the beach
50-10= 40 miles/h to get home
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70 POINTS !! Charlotte has a map of the village. The scale on the map is such that 1cm represents 25m.
Natasha_Volkova [10]

Answer:

A. 175 m

B. 20 cm

Step-by-step explanation:

\frac{1 cm}{25 m} =\frac{7 cm}{x m}

x = 175 m

\frac{25 m}{1 cm} = \frac{500 m}{x cm}

x = 20 cm

5 0
2 years ago
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What’s the domain and range for this? And is it a function? Yes or No
lara [203]

You are given the domain and range ( the numbers in each oval):

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Domain (-4,0,6,6)

Range (12,18,18,40)

To be a function each input value ( Domain) can only have one output value (range)

Because the 6 has two different outputs ( 12, 18) this is not a function.

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2 years ago
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Round the following numbers to the tenths place.<br> 1. 1295.9549
yKpoI14uk [10]
1,296.0 I think this is right, I apologize if it’s wrong.
6 0
3 years ago
A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts ar
kompoz [17]

Answer:

The probability that more than 35 were made is 0.14686.

Step-by-step explanation:

We are given that a professional basketball team made 37.9% of its three-point field goals in one season.

80 three-point field goal attempts are randomly selected from the season.

Let \hat p = <em>sample proportion of three-point field goals made in one season.</em>

The z-score probability distribution for the sample proportion is given by;

                           Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }  ~ N(0,1)

where, p = population proprotion of three-point field goals = 37.9% = 0.379

            n = sample of three-point field goal attempts = 80

            \hat p = sample proportion of three-point field goals = \frac{35}{80} = 0.4375

Now, if 80 three-point field goal attempts are randomly selected from the season, the probability that more than 35 were made is given by = P(\hat p > 0.4375)

P(\hat p > 0.4375) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} } > \frac{0.4375-0.379}{\sqrt{\frac{0.4375(1-0.4375)}{80}} } ) = P(Z > 1.05) = 1 - P(Z \leq 1.05)

                                                                       = 1 - 0.85314 = <u>0.14686</u>

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

4 0
4 years ago
PLEASE HELP ASAP THIS IS DUE SOON
Alla [95]

Answer:

True

Step-by-step explanation:

5 0
3 years ago
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