-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11
*note negative times a negative equals positive and negative times positive is negative
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m
sixth: combine like terms
seventh: answer
Answer: x = $7, y = $6
Step-by-step explanation:
Let x be the cost of an adult ticket
Let y be the cost of a children's ticket
Translate these sentences to algebra:
At the circus, three adult tickets and five child tickets cost $51: 3x + 5y = 51
Five adult tickets and two child tickets cost $47: 5x + 2y = 47
Now we have two equations. Let's use substitution to solve.
3x + 5y = 51
3x = 51 - 5y
.: x = 17 - 5y/3
Now substitute this value of x into the second equation to find the numerical value of y:
5(17 - 5y/3) + 2y = 47
85 - 25y/3 + 2y = 47
-19y/3 = -38
-19y = -114
.: y = 6
Now find x:
x = 17 - 5y/3
x = 17 - 10
.: x = 7
So an adult ticket costs $7, and a child ticket costs $6 :)
We assume that the function is as follows:
Then, we have that:
Thus, if we have that:
Therefore, the value for the function is f^-1(2) = -1/2 or
Sum of two interiors=exterior
Mult. the 2nd eqn by 6 and then add this "new" equation to the 1st given eqn:
-6x + y = -2
6x -18y = 54
--------------------
-17y = 52, or y = -52/17. Subst. this value of y into either equation to find the value of x.
