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2 years ago

Anybody good in geometry? And know this? Free Brainliest and points

Mathematics

2 answers:

Igoryamba2 years ago

7 0

Answer:

The answer is C.

Step-by-step explanation:

svp [43]2 years ago

4 0

RST reflected directly over the y-axis would give the prime letters. It is a direct reflection. The answer is C.

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Can someone do these questions 1-3 please i have an F in math now :/

ruslelena [56]

Answer:

There is no picture.

Step-by-step explanation:

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2 years ago

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I need assistance if anyone would be so kind.

uysha [10]

He shoots 20 arrows

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2 years ago

Determine the amplitude and period of each function without graphing.

Luba_88 [7]

Answer:

Step-by-step explanation:

We know for a function:

y = Asinωt

=> on comparison, <u>A = 5 m</u>

=> T = 2π / ω

=> T = 2π / 2

=> <u>T = π seconds</u>

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2 years ago

Sarah takes out a loan for $30,000. She has two choices for the loan; a 5 year loan with 5% simple interest or a 7 year loan wit

aivan3 [116]

Answer:

$1977.95

Step-by-step explanation:

$30000*.05*5=$7500 (simple interest)

$30000*1.04^7=$39477.95-$30000=$9477.95 (compound interest)

$9477.95-$7500.00=$1977.95

4 0

3 years ago

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Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will

slavikrds [6]

Answer:

$\text{tan}(\theta)=\frac{\sqrt{119}}{5}$

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity $\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$ . She is told that $0\leq \theta\leq \frac{\pi}{2}$ and $\text{cos}(\theta)=\frac{5}{12}$ .

First of all, we will find value of sine theta using the given identity.

$\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$

$\text{sin}^2(\theta)+(\frac{5}{12})^2=1$

$\text{sin}^2(\theta)+\frac{25}{144}=1$

$\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}$

$\text{sin}^2(\theta)=\frac{144-25}{144}$

$\text{sin}^2(\theta)=\frac{119}{144}$

$\text{sin}(\theta)=\sqrt{\frac{119}{144}}$

$\text{sin}(\theta)=\frac{\sqrt{119}}{12}$

$\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}$

$\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}$

$\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}$

Therefore, $\text{tan}(\theta)=\frac{\sqrt{119}}{5}$ .

5 0

3 years ago