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3 years ago

What is the solution of the equation 1.6m - 4.8 = -1.6m

1 answer:

6 0

Solve for m:
1.6 m - 4.8 = -1.6 m

Add 1.6 m to both sides:
1.6 m + 1.6 m - 4.8 = 1.6 m - 1.6 m

1.6 m - 1.6 m = 0:
1.6 m + 1.6 m - 4.8 = 0

1.6 m + 1.6 m = 3.2 m:
3.2 m - 4.8 = 0

Add 4.8 to both sides:
3.2 m + (-4.8 + 4.8) = 4.8

4.8 - 4.8 = 0:
3.2 m = 4.8

Divide both sides of 3.2 m = 4.8 by 3.2:
(3.2 m)/3.2 = 4.8/3.2

3.2/3.2 = 1:
m = 4.8/3.2

4.8/3.2 ≈ 1.5:
Answer: m ≈ 1.5

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Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

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Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

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All the other numbers in between can be divided by something and not become a decimal. Other than 23, it can be divided by anything without becoming a decimal.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
<em>~Hope this helped :)</em>

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