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soldi70 [24.7K]
3 years ago
13

What is 3.55 divided by 5 equal 3 tenthsdivided by 5 + 5 hundredths divided by 5 equal

Mathematics
1 answer:
levacccp [35]3 years ago
7 0
No it is not equal. 3.55 divided by 5=0.71.    0.3 divided by 5+ 0.05 divided by 5 equals to 0.07.
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X2−3x−10 ( x - 4 ) ( x + 2 ) ( x - 4 ) ( x + 2 ) ( x - 5 ) ( x + 2 ) ( x - 5 ) ( x + 2 ) ( x + 8 ) ( x - 1 ) ( x + 8 ) ( x - 1 )
loris [4]

Answer:

(x+2)(x-5)

Step-by-step explanation:

Given the expression X^2−3x−10, we are to factorize it;

On factorizing;

= x² - 5x + 2x - 10

= x(x-5) + 2(x - 5)

= (x+2)(x-5)

Hence the factored form of the expression is (x+2)(x-5)

8 0
3 years ago
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IgorLugansk [536]

Answer:

6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help me out please
saul85 [17]

The surface area of the geometric shape is B. 840 cm².

Step-by-step explanation:

Step 1:

The given figure is made up of three rectangles and two triangles.

The surface area of the geometric shape is given by summing the individual surface areas.

The geometric shape's surface area = The sum of the individual surface areas.

Step 2:

The surface area of the rectangles is the multiplication of its length and width.

The surface area of the rectangle with length z and width x = (26)(10)= 260 cm^{2}.

The surface area of the rectangle with length y and width x = (24)(10)= 240 cm^{2}.

The surface area of the rectangle with length x and width x = (10)(10)= 100 cm^{2}.

Step 3:

The area of a triangle is half the product of its base length and height.

The surface area of a triangle with base y and height x= \frac{1}{2} (24)(10) = 120 cm^{2}.

They are two similar triangles so their areas are equal

Step 4:

The geometric shape's surface area = 160 + 240+100+120+120 = 840 cm^{2}.

So the surface area is option B. 840 cm².

5 0
3 years ago
Y = -4.5x + 15<br><br> is this not a function, linear function, or nonlinear function
crimeas [40]
This is a linear function
5 0
3 years ago
A line passes through the points 3,10 and 6, 16 write the equation of this line in slope-intercept form
cluponka [151]

(\stackrel{x_1}{3}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{16}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{16}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{3}}} \implies \cfrac{ 6 }{ 3 } \implies 2

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{ 2}(x-\stackrel{x_1}{3}) \\\\\\ y-10=2x-6\implies {\Large \begin{array}{llll} y=2x+4 \end{array}}

4 0
1 year ago
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