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nalin [4]
3 years ago
14

Click on the measure of angle x. х 38° » 152 1)) 142° () 38° )) 52°

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

142°

Step-by-step explanation:

180^{\circ} - 38^{\circ} = 142^{\circ}

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(-5)^2-2x(-9)+6<br> Please show work and step by step.
Varvara68 [4.7K]

Answer:

<h2>49</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

==============================================

(-5)² - 2 × (-9) + 6          <em>first </em><em>E</em><em>xponents</em>

25 - 2 × (-9) + 6          <em>next </em><em>M</em><em>ultiplication</em>

25 + 18 + 6              <em>next </em><em>A</em><em>ddition</em>

43 + 6 = 49

5 0
3 years ago
What would you do if you saw a to 99 year old women fighting over a 21 year old man
Sophie [7]

Answer:

kick them to the moon. <D

Step-by-step explanation:

it's probably wrong- but that's what i'd do lolol

3 0
3 years ago
Does anyone know this lol i just need a short explanation
maks197457 [2]

Answer: pretty sure it’s because the left and bottom sides add up to equal the top side

Step-by-step explanation:

4 0
2 years ago
What is the area of rectangle abcd with 12 in length and 4 in width
nikitadnepr [17]

Answer: It would be

A=48    

5 0
2 years ago
Read 2 more answers
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
2 years ago
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