This could have happened when:
- Lack of Internet service or failure
- Wrong application.
<h3>What do you mean by Internet?</h3>
The Internet is seen as a form of a network that helps people to connects their computers all over the nation.
In this age, Through the help of the Internet, people are able to share information and navigate through places.
Note that the problem of bad direction could have happened when:
- Lack of Internet service or failure
- Wrong application.
Learn more about Internet from
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Cloud computing, also known as cloud services, cloud concepts or simply the cloud, is a paradigm that allows to offer computer services. through a network, which is usually the Internet.
(data persistence, authentication, messaging, etc.). for example, a Linux system, a web server, and a programming environment such as Perl or Ruby).
Commercial examples are Google App ,Microsoft Azure,
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
edit is the 5th and distribute is the final stage in process of media production
Answer:
Raid 0
Explanation:
Raid 0 is a configuration used for speed priority. Datas are stored differently on each disk
