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yarga [219]
3 years ago
7

Help it's the last question quickkk​

Computers and Technology
1 answer:
aniked [119]3 years ago
7 0
I would say the answer is b, but ⟟ might be wrong
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Just do it just look up the answers mate
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3 years ago
1. What are the advantages and disadvantages of technology in communication?
Gennadij [26K]

Answer:

ADVANTAGES:

First, the evolution of technology is beneficial to humans for several reasons. At the medical level, technology can help treat more sick people and consequently save many lives and combat very harmful viruses and bacteria.

2-Technology has also increased the productivity of almost every industry in the world. Thanks to technology, we can even pay with bitcoins instead of using banks

DISADVANTAGES:

1-Lack of Privacy. You might think that a quick text or IM offers more privacy than a telephone call in a crowded room. ...

2-Distraction from Real Life. ...

3-Potential for Misunderstanding. ...

4-Decline of Grammar and Spelling...

5- Near people are far and far people are near through communication technology. we have no time to sit with our relatives but constantly communicate far away people . I think this is biggest <em>disadvantage </em>

Explanation:

7 0
3 years ago
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Each of the following are advanced strategies you may use to help you conduct a search on the Internet except _____. using a wil
malfutka [58]

i cant see anything tho theres nothing there

4 0
3 years ago
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// In this exercise, you will be given a variable, it will be called: value
rjkz [21]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {      

     Scanner scan = new Scanner(System.in);

     System.out.println("Enter your value");

     int value = scan.nextInt();      

     greaterThanFive(value);

   }  

   public static void greaterThanFive(int userInput){

       System.out.println(userInput > 5);

   }

}

Explanation:

The first line import the Scanner which is use to enable to accept user input.

The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.

Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.

The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).

8 0
3 years ago
Given an array temps of double s, containing temperature data, compute the average temperature. Store the average in a variable
Ket [755]

Answer:

#include <iostream>

using namespace std;

// average function

void average(double arr[], int n) {

double total = 0;

double avgTemp;

for (int i = 0; i < n; i++)

{

 // find temperatures total

 total = total + arr[i];

}

// find average

avgTemp = total / n;

cout << "\nAverage Temperature = " << avgTemp << endl;

}

// print temps[] array

void printArray(double arr[], int n) {

for (int i = 0; i < n; i++)

{

 cout << arr[i] << "   ";

}

}

int main() {

int const k = 5;

double temps[k];

// temperature value

double tempValue;  

// Enter 5 temperatures of your choice

for (int i = 0; i < k; i++)

{

 cout << "Enter Temperature value " << i+1 << ": ";

 cin >> tempValue;

 temps[i] = tempValue;

}

// Function call to print temps[] array

printArray(temps, k);  

// Function call to print average of given teperatures

average(temps, k);        

return 0;

}

Explanation:

• Inside main(), int constant k is created to set the maximum size of array temps[].

• tempValue of  type double takes value at a given index of our temps[] array.

• the for loop inside main() is used to get tempValue from the user and store those values in our array temps[].

• after that printArray() function is called. to pass an array to a function it requires to perimeters 1) name of the array which is temps in our case. 2) maximum number of the index which is  k.

• note the syntax of void average(double arr[], int n). Since we are passing an array to the function so its formal parameters would be arr[] and an int n which specifies the maximum size of our array temps[].

6 0
3 years ago
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