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anyanavicka [17]
3 years ago
6

what is the sum of an 8th term geometric series if the first term is -11, the last term is 180,224, and the common ratio is -4

Mathematics
1 answer:
Mumz [18]3 years ago
4 0

The sum of n terms is given from the first term and the common ratio by

S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}

For your given values of a1=-11, r=-4, n=8, the sum of 8 terms is

S_{8}=(-11)\dfrac{(-4)^{8}-1}{-4-1}=(-11)\dfrac{65535}{-5}\\\\=144177

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Marizza181 [45]

Are you solving for t?

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Answer:

13. c,

14. a.

Step-by-step explanation:

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\sqrt{(5-5)^{2}+(-2+7)^{2}  } =\sqrt{0^{2}+5^{2}  } =5

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\sqrt{(5-1)^{2}+(-7+2)^{2}  } =\sqrt{(4)^{2}+(-5)^{2}  } =\sqrt{4^{2}+5^{2}  }

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now, the easiest one will be when the vertices are on the coordinate axes.

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the parallel postulate, i.e, the alternate interior angles will always be congruent.

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7 0
3 years ago
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Svet_ta [14]
Hello,
Here is the formula to find the area of the trapezoid:
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b2 represent small base
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Answer:

A

Step-by-step explanation:

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4 0
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