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anyanavicka [17]
3 years ago
6

what is the sum of an 8th term geometric series if the first term is -11, the last term is 180,224, and the common ratio is -4

Mathematics
1 answer:
Mumz [18]3 years ago
4 0

The sum of n terms is given from the first term and the common ratio by

S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}

For your given values of a1=-11, r=-4, n=8, the sum of 8 terms is

S_{8}=(-11)\dfrac{(-4)^{8}-1}{-4-1}=(-11)\dfrac{65535}{-5}\\\\=144177

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