All categories

3 years ago

Identify the zeros of the function graphed below

Mathematics

2 answers:

EastWind [94]3 years ago

5 0

It doesn’t pass through any zeros of the function

hram777 [196]3 years ago

3 0

Dmdjjsdkfjjskdk I like glizzy.con sksksksk

You might be interested in

What is f(x) = 7x2 + 42x written in vertex form?

amid [387]

Answer:

$\boxed{\boxed{y = 7(x+3)^2-63}}$

Step-by-step explanation:

The general vertex form of parabola is,

$y=a(x-h)+k$

where,

(h, k) is the vertex of the parabola.

The given function is,

$\Rightarrow f(x) = 7x^2 + 42x$

$\Rightarrow y = 7x^2 + 42x$

$\Rightarrow y = 7(x^2 + 6x)$

$\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3)$

$\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3+3^3-3^2)$

$\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3+3^3)-7\cdot 3^2$

$\Rightarrow y = 7(x+3)^2-7\cdot 9$

$\Rightarrow y = 7(x+3)^2-63$

This is vertex form the given function.

7 0

3 years ago

Read 2 more answers

Is 3 yards bigger than 21 feet is 21 feet bigger than 3 yards

Kipish [7]

No because 21 ft equals 7 yd
which us bigger than 3 yd

6 0

3 years ago

Read 2 more answers

Write an equation of the line passing through each of the following pairs of points. (4,-8), (0,2)

ollegr [7]

Step-by-step explanation:

m= $\frac{2-(-8)}{0-4}$ = $\frac{10}{-4}$ = -2.5

this may be right but I do not know

7 0

3 years ago

What is the equation of the line x–3y=18 in slope-intercept form?

Minchanka [31]

Answer:

Simple...

you have: x-3y=18

You want to convert it into slope-intercept form or y=mx+b form-->>>

x-3y=18

Isolate the variable-->>

x-3y=18

-x -x

-3y=-x+18

Now simply divide...

-3y/-3 = -x+18/-3

y=1/3x=6

Thus, your answer.

3 0

3 years ago

Read 2 more answers

Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco

chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

$f(t) = \frac{1}{3}t^3-\frac{5}{2}t^2 + 80$

$f'(t) = t^2-5t$

Substitute f'(t)=0.

$t^2-5t=0$

$t(t-5)=0$

$t=0\ or\ t=5$

It is given that (0 ≤ t ≤ 10)

The test interval are (0,5) and (5,10)

For (0 < t < 5) the value of $f'(t)$

For (5 < t < 10) the value of $f'(t) >0$

Hence, the function is increasing from (5,10).

t = 0 corresponds to 2004.

Therefore, after 2009 the quality of the forests in this country improving.

7 0

3 years ago