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Katena32 [7]
3 years ago
10

∠BCD is reflected over the x-axis. If m∠BCD = 35°, what is the measure of ∠BʹCʹDʹ ?

Mathematics
1 answer:
SashulF [63]3 years ago
6 0
The angle should not change. 35 degrees
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Sunny_sXe [5.5K]
H(d)=height from water
when he reaches the water, his height from water=0

so set the equation equal to zero and solve

0=-d^2+2d+24
multiply both sides by -1 for ease
0=d^2-2d-24
now find what 2 factors of -24 add up to -2
answer is -6 and 4
0=(d-6)(d+4)
set each to zero
d-6=0
d=6

d+4=0
d=-4
you cannot have negative distance  because that means he hasn't jumped yet so get rid of this number

d=6

answer is 6 meters
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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
Austin is comparing the prices of two truck rental companies. Company A charges $4 per hour and an additional $70 as service cha
solniwko [45]
A(h)=4h+70, A(h)=dollars to rent for h hours, h=hours rented.

B(h)=5h+60,  same variable explanations...

....

To compare the two values at 6 hours you have:

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So at 6 hours Company B would charge $4 less than Company A

...

Savings at 7 hours of rental by using B instead of A is:

S(h)=A(h)-B(h)

S(h)=4h+70-5h-60

S(h)=-h+10

S(7)=-7+10=$3

So at 7 hours, Company B saves you $3.
5 0
3 years ago
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