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3 years ago

∠BCD is reflected over the x-axis. If m∠BCD = 35°, what is the measure of ∠BʹCʹDʹ ?

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

The angle should not change. 35 degrees

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Answer:

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}$

Multiply the row of the first matrix to the column of the second matrix

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1$

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\$

$=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}$

simplifying them we get

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

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Add. Write your answer in simplest form.

alexandr1967 [171]

Answer:

yes, you got it correct

Step-by-step explanation:

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