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murzikaleks [220]
2 years ago
9

Help me find the media, mode and the mean look at the photo and solve the puzzle

Mathematics
1 answer:
svp [43]2 years ago
3 0

Answer: See below.

Good Luck! I hope this helps!

Step-by-step explanation:

1) Find the Mean of 7  18  9  22  4.

7 + 18 + 9 + 22 + 4 = 50

50 ÷ 5 = 10

2) Find the Median of 7  18  9  22  4.

4  7  9  18  22

The Median is 9.

3) Find the Mean of 7  3  7  4  8  9  2.

7 + 3 + 7 + 4 + 8 + 9 + 2 = 40

40 ÷ 7 = 5.7

4) Find the Median of 7  3  7  4  8  9  2.

2  3  4  7  7  8  9

The Median is 7.

5) Find the Mode of 7  3  7  4  8  9  2.

Mode is the number that occurs the most.

2  3  4  7  7 8  9

The Mode is 7.

6) Find the Median of 6  10  23  24  13  9  23  12.

6  9  10  12  13  22  23  24

There are 8 numbers in this set of numbers, so the Median is the average of the two numbers in the middle. So, \frac{(12+13)}{2} = \frac{25}{2} = 12.5

The Median is 12.5.

7) Find the Mean of  6  10  23  24  13  9  23  12.

6 + 10 + 23 + 24 + 13 + 9 + 23 + 12 = 120

120 ÷ 8 = 15

The Mean is 15.

8) Find the Median of 120  113  101  101  112.

101  101  112  113  120

The Median is 112.

9) Find the Mean of 73  72  72  98  99  96  98  98  73.

73 + 72 + 72 + 98 + 99 + 96 + 98 + 98 + 73 = 779

779 ÷ 9 = 86.6.

10) Find the Mode of 73  72  72  98  99  96  98  98  73.

72  72  73  73  96  98  98  98  99

The Mode is 98.

11) Find the Mode of 6  10  23  24  22  9  23  13.

6  9  10  13  22  23  23  24

The Mode is 23.

12) Find the Median of  73  72  72  98  99  96  98  98  73.

72  72  73  73  96  98  98  98  99

The Median is 96.

13) Find the Median of 12  22  26  15  18  22  29  11  22  18.

11  12  15  18  18  22  22  22  26  29

There are 10 numbers in this set of numbers, so the Median is the average of the two numbers in the middle. So, \frac{(18+22)}{2} = \frac{40}{2} = 20

The Median is 20.

<h2>THE END!  Yay!</h2>
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\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

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<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

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