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Vlad [161]
3 years ago
14

The length of a garden is 51 1/3 feet. One section of fencing is 3 2/3 feet long.

Mathematics
2 answers:
sveta [45]3 years ago
7 0
Part A - 14 sections of fencing

Part B - 0.9165 the distance between each stake
nadezda [96]3 years ago
4 0

\\(A)\\
\text{Given that the length of the garden is}=51\frac{1}{3}=\frac{154}{3} \text{ feet}\\
\text{and the length of one section of fencing is}=3\frac{2}{3}=\frac{11}{3}\text{ feet}\\
\\
\text{hence the total number of sections of fencing needed along}\\
\text{the length of the garder are:}\\
\\
=\frac{154/3}{11/3}\\
\\
=\frac{154}{3}\times \frac{3}{11}\\
\\
=\frac{462}{33}\\
\\
=14
\\
\text{Hence the total number of sections of fencing needed are:}

14

\\(B)\\
\text{For each piece of fencing , 4 stakes are used to secure it in place.}\\
\text{The stakes are equally spaced along the fencing With one stake at each end. }\\
\\
\text{so we need to divide the length of fencing in three equal parts}\\
\text{seperated by 4 stakes. so the length between two stakes is}\\
\\
=\frac{11/3}{3}\\
\\
=\frac{11}{3\times 3}\\
\\
=\frac{11}{9}\\
\\
\approx 1.22

Hence, the stakes are approximately 1.22 feet from each other on one piece of fencing.

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Answer:

A) The probability that each player gets an ace, a 2 and a 3 with the order unimportant = (72/1925) = 0.0374

B) The probability of winning the jackpot = (1/1200) = 0.0008333

Step-by-step explanation:

A) There are four Aces, four 2's, and four 3's, forming a set of 12 cards

These cards are to be divided at random between 4 players.

What is the probability that each player gets an ace, a 2 and a 3.

We start with the first player, the probability of these cards for the first player, with order not important (because order isn't important, there are 6 different arrangement of the 3 cards)

6 × (4/12) × (4/11) × (4/10) = (16/55)

Then the second player getting that same order of cards

6 × (3/9) × (3/8) × (3/7) = (9/28)

Third player

6 × (2/6) × (2/5) × (2/4) = (2/5)

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6 × (1/3) × (1/2) × (1/1) = 1

Probability that each of the players get different cards is then a multiple of the probabilities obtained above

= (16/55) × (9/28) × (2/5) × 1

= (288/7700) = (72/1925) = 0.0374

B) The concluding part of the B question.

To win the jackpot, the numbers on your ticket must match the three white balls and the SuperBall. (You don't need to match the white balls in order). If you buy a ticket, what is your probability of winning the jackpot?

Probability of wimning the jackpot is a product the probability of getting the 3 white balls correctly (order unimportant) and the probability of picking the right red superball

Probability of picking 3 white balls from 10

First slot, any of the 3 lucky numbers can fill this slot, (3/10)

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Third slot, only 1 remaining lucky number can fill this slot, (1/8)

(3/10) × (2/9) × (1/8) = (1/120)

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(1/10)

Probability of winning the jackpot = (1/120) × (1/10) = (1/120) × (1/10) = (1/1200) = 0.0008333

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