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Vlad [161]
3 years ago
14

The length of a garden is 51 1/3 feet. One section of fencing is 3 2/3 feet long.

Mathematics
2 answers:
sveta [45]3 years ago
7 0
Part A - 14 sections of fencing

Part B - 0.9165 the distance between each stake
nadezda [96]3 years ago
4 0

\\(A)\\
\text{Given that the length of the garden is}=51\frac{1}{3}=\frac{154}{3} \text{ feet}\\
\text{and the length of one section of fencing is}=3\frac{2}{3}=\frac{11}{3}\text{ feet}\\
\\
\text{hence the total number of sections of fencing needed along}\\
\text{the length of the garder are:}\\
\\
=\frac{154/3}{11/3}\\
\\
=\frac{154}{3}\times \frac{3}{11}\\
\\
=\frac{462}{33}\\
\\
=14
\\
\text{Hence the total number of sections of fencing needed are:}

14

\\(B)\\
\text{For each piece of fencing , 4 stakes are used to secure it in place.}\\
\text{The stakes are equally spaced along the fencing With one stake at each end. }\\
\\
\text{so we need to divide the length of fencing in three equal parts}\\
\text{seperated by 4 stakes. so the length between two stakes is}\\
\\
=\frac{11/3}{3}\\
\\
=\frac{11}{3\times 3}\\
\\
=\frac{11}{9}\\
\\
\approx 1.22

Hence, the stakes are approximately 1.22 feet from each other on one piece of fencing.

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A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w
sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations  = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

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3 years ago
Subtract 3 1/2 from 5 1/3
AleksAgata [21]

Answer:

11/6

Step-by-step explanation:

16/3 - 7/2 = 16/3 x 2/2 - 7/2 x 3/3 = 32/6 - 21/6 = 32-21/6 = 11/6

8 0
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Draw an example of a composite figure that has a volume between 750 cubic inches and 900 cubic inches
grigory [225]

Volume:

V \approx 888.02in^3 \\ \\ And, \ 750in^3

<h2>Explanation:</h2>

A composite figure is formed by two or more basic figures or shapes. In this problem, we have a composite figure formed by a cylinder and a hemisphere as shown in the figure below, so the volume of this shape as a whole is the sum of the volume of the cylinder and the hemisphere:

V_{total}=V_{cylinder}+V_{hemisphere} \\ \\ \\ V_{total}=V \\ \\ V_{cylinder}=V_{c} \\ \\ V_{hemisphere}=V_{h}

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V_{c}=\pi r^2h \\ \\ r:radius \\ \\ h:height

From the figure the radius of the hemisphere is the same radius of the cylinder and equals:

r=\frac{8}{2}=4in

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The volume of a hemisphere is half the volume of a sphere, hence:

V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi r^3\right) \\ \\ V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi (4)^3\right) \\ \\ V_{h}=\frac{128}{3}\pi in^3

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<h2>Learn more:</h2>

Volume of cone: brainly.com/question/4383003

#LearnWithBrainly

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Time= t years

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