How to find the shaded region of a circle with a rectangle inside?

1 answer:

8 0

You would start by finding the area of the circle and then finding the area of the rectangle. After finding both, subtract the area of the rectangle from that of the circle. <span />

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Help Please!<br><br> Solve for d.<br> 5+d>5−d<br><br> Solve for p.<br> 2p+3>2(p−3)

Keith_Richards [23]

<span>Solve for d.
5+d>5−d Subtract 5 from both sides of this inequality:

d>d There is no value for d that satisfies this inequality.
No value can be greater than itself.

</span><span>Solve for p.
2p+3>2(p−3) Multiply this out: 2p+3>2p-6
</span><span> Subtr 3 from both sides: 2p> 2p-9

This is equivalent to 2p+9>2p.
We could subtr. 2p from both sides: 0>-9.

0> -9 is always true. Thus, the given inequality has infinitely many solutions.

</span>

3 0

3 years ago

Algebra graphing question

expeople1 [14]

Answer:

Graph

Step-by-step explanation

Make a point in between -1 and 0. This will be your X value. Then on the y axis make a point on -1. Connect the 2 points with a line

6 0

4 years ago

Read 2 more answers

Any idea on how to solve this?

hichkok12 [17]

If you are talking about finding the slope of BC then it looks like you have to find the square root of 3 which is approx 1.7 then find the slope.
slope equation is rise over run (or y over x): y1 + y2 divided by x1 + x2.
From this you should be able to find the answer

8 0

3 years ago

How can (4x⁵/2x²)³ be solved in 2 different ways

Margaret [11]

We assume that we need to simplify the expression in two different ways.

Answer:

One way: Raise both, the numerator and denominator, to the third power, and then simplify the expression.

Second way: Simplify the terms inside parentheses, and then raise the result to the third power.

The result of both ways is the same: $\\8x^{9}$