F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4
Answer:
(1,1)
Step-by-step explanation:
The choices are not visible, however are unnecessary to solve this problem.
Given y = 3x - 2 and y = -2x + 3
[Set them equal to each other]
3x - 2 = -2x + 3
[Find x]
3x + 2x - 2 = 3
3x + 2x = 5
5x = 5
x = 1
[Plug x = 1 to both equations to check and find y]
y = 3x - 2
y = 3(1) - 2 = 3 - 2 = 1
y = -2x + 3
y = -2(1) + 3 = -2 + 3 = 1
Both are equal to y = 1 when x = 1
The point is then: (1,1)
The answer is 1/16 i think. Hope this helps! :)
Answer:
x= -3 or 4/3
Step-by-step explanation:
3x²+5x-12 =0
3x²+9x-4x-12=0
3x(x+3) -4(x+3) =0
(3x-4)(x+3)=0
x=-3 or 4/3
