Answer:
D. 1.49
Step-by-step explanation:
_________________
Answer:
The sum of three-fourths of w, five-sixths of p, and 9
= 3/4w + 5/6p + 9
For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
