Answer:
Randy has eight $5 bills and nine $1 bills
Step-by-step explanation:
Randy needs $50.00
And we know that he his only $1.00 short, so he has $49.00
let's define:
x = number of $1 bills that he has
y = number of $5 bills that he has.
then:
x*$1 + y*$5 = $49
We know that he has one more $1 bills than $5 bills.
we can write this as
x = y + 1
So we have a system of two equations and two variables:
x*$1 + y*$5 = $49
x = y + 1
First we can see that the variable "x" is isolated in the second equation, now we can replace that in the other equation:
x*$1 + y*$5 = $49
(y + 1)*$1 + y*$5 = $49
now we can solve this for y.
y*$1 + $1 + y*$5 = $49
y*($1 + $5) = $49 - $1 = $48
y*$6 = $48
y = $48/$6 = 8
He has 8 $5 bills
and we know that:
x = y + 1
x = 8 + 1 = 9
he has 9 $1 bills.
Answer:
90 in²
Step-by-step explanation:
First,check the figure I provided .
Area of the figure = area1 + area2 + area3 + area4
= (3×2) + (7×7) + (7×2) + (7×6)÷2
= 6 + 49 + 14 + 21
= 90
Answer:
x=4
Step-by-step explanation:
Consider the coordinate pair (4,y)
We observe that,
y can take any real values to lie on the graph of the equation.
As y really isn't a constant, we exclude it and take the equation as x=4
C. f(x)= log 1/x^2 , c=/ 0
